用户定义的公共变量 yii2 模型打印空值答案

【问题标题】：User defined public variables yii2 model prints empty value用户定义的公共变量 yii2 模型打印空值
【发布时间】：2017-11-05 18:26:47
【问题描述】：

我在我的 yii2 前端用户模型中定义了一些值，我的模型名称是 'PhCabinetUser' 以下是我的模型中的代码。

class PhCabinetUser extends \yii\db\ActiveRecord
{


public $has_liveaccount;
public $email_verification;
public $account_deposited;
public $document_uploaded;

/**
 * @inheritdoc
 */
public static function tableName()
{
    return 'ph_cabinet_user';
}

现在，当我尝试在控制器中获取 $email_verification 时，它返回空值。

以下是来自我的控制器的代码。

$model = PhCabinetUser::find()->all();
    $row = array();

    foreach($model as $obj) {
  echo $obj['email_verification'];
  echo $obj->email_verification;
   }

但是，当我打印 $obj 数组时，它显示 email_verification 的值以下是我的 print_r($obj) 结果。

crm\models\PhCabinetUser Object ( [has_liveaccount] => [email_verification] => [account_deposited] => [document_uploaded] => [_attributes:yii\db\BaseActiveRecord:private] => Array ( [id] => 29 [company_id] => 1 [first_name] => Super [last_name] => Man [username] => ksdwpfr3.a4q@20email.eu [email] => ksdwpfr3.a4q@20email.eu [registration_email_token] => PXwTu8KULal2_So5U3wVllxfKg1X-Dzh_1468296370 [country] => 2 [country_code] => +355 [phone] => 1234567890 [dob] => [gender] => male [address1] => [address2] => [city] => [state] => [zipcode] => [source] => Website [owner] => 1 [lead_manager] => [has_liveaccount] => 0

[email_verification] => 1

[account_deposited] => 0 
[document_uploaded] => 0 
[lead_status] => 1 
[status] => 10 
[created_at] => 1468296369 [updated_at] => 1468296580 ) 

[_oldAttributes:yii\db\BaseActiveRecord:private] => Array ( 
[id] => 29 
[company_id] => 1 
[first_name] => Super 
[last_name] => Man 
[username] => ksdwpfr3.a4q@20email.eu 
[auth_key] => Nc-GABmcqJIpib22L5cuwgBaOKqRvbiQ 
[password_hash] => $2y$13$ZHB6IF51LODVqAEwI2zRkuIWbgEZ165acvpIeiVm2SZBFA1kzpp4S 
[password_reset_token] => 
[email] => ksdwpfr3.a4q@20email.eu 
[registration_email_token] => PXwTu8KULal2_So5U3wVllxfKg1X-Dzh_1468296370 
[country] => 2 
[country_code] => +355 
[phone] => 1234567890 
[dob] => 
[gender] => male 
[address1] => 
[address2] => 
[city] => 
[state] => 
[zipcode] => 
[source] => Website 
[owner] => 1 
[lead_manager] => 
[has_liveaccount] => 0 
[email_verification] => 1 
[account_deposited] => 0 
[document_uploaded] => 0 
[lead_status] => 1 
[status] => 10 
[created_at] => 1468296369 
[updated_at] => 1468296580 
) 
[_related:yii\db\BaseActiveRecord:private] => Array ( ) 
[_errors:yii\base\Model:private] => 
[_validators:yii\base\Model:private] => 
[_scenario:yii\base\Model:private] => default [_events:yii\base\Component:private] => Array ( ) [_behaviors:yii\base\Component:private] => Array ( ) )

现在如何在变量中获取这个值。

【问题讨论】：

而不是做回声，通过 var_dump 检查一次，我想它必须是布尔值
是的，它是布尔变量。那么如何打印呢？
为什么在ActiveRecord类模型中使用成员变量
Echo 无法在此工作。做var_dump，在if条件下可以直接使用
if 条件下如何使用。我试过这个 if($obj['email_verification']==1) { echo "works"; } 但它不工作

标签： php yii yii2

【解决方案1】：

确保您在班级顶部添加的公共 var 不会覆盖您的 ActiveRecord .. 您在活动记录中已经有相同的 var 名称 .. 在模型中声明公共 var 会生成失败赋值，你得到空结果..

【讨论】：

【解决方案2】：

试试看：

if($obj->email_verification) {
echo "Works";
}

【讨论】：

什么是 var_dump($obj->email_verification);结果

【解决方案3】：

试试

$model = PhCabinetUser::find()->all();
var_dump($model); exit;

【讨论】：