无法使用多个 LEFT JOIN 提取数据

Question

我需要提取所有匹配到特定日期的国家，表格结构是这样的：

TABLE NAME  |  FIELDS
country     | id, name  
round       | id, season_id
season      | id, competition_id
competition | id, country_id
match       | id, round_id, date

单个match 记录具有以下组成：

id: 60856
round_id: 65
date: 2018-06-02 00:00:00

如您所见，我有 round_id，其中 match 存在争议。 在round 表上有如下设计：

id: 65
season_id: 280

season 代表round 的容器，因此season 记录具有以下结构：

id: 161
competition_id: 48

和一个season 有一个包含所有rounds 的competition。一条competition 记录包含country：

id: 48
coutry_id: 2

最后是country:

id: 2
name: albania

我如何提取所有有今天比赛的国家？

这是我尝试过的：

$app->get('/country/get_countries/{date}', function (Request $request, Response $response, array $args)
{
    $sql = $this->db->query("SELECT * FROM country
      LEFT JOIN `match` ON round_id = round.id
      LEFT JOIN round ON season_id = season.id
      LEFT JOIN season ON competition_id = competition.id
      WHERE match.datetime = " . $args["date"] . "");

    $sql->execute();
    $countries = $sql->fetchAll();
    return $response->withJson($countries);
});

这将返回：

SQLSTATE[42S22]：未找到列：1054 'on 子句'中的未知列 'round.id'

更新：

  $sql = $this->db->query("SELECT * FROM country
  LEFT JOIN competition ON country_id = competition.country_id
  LEFT JOIN competition_seasons ON competition_id = competition.id
  LEFT JOIN competition_rounds ON competition_rounds.season_id = competition_seasons.id
  LEFT JOIN `match` ON match.round_id = competition_rounds.id
  WHERE match.datetime = " . $args["date"] . "");

Answer 1

SELECT * FROM country
      LEFT JOIN competition ON country.id = competition.country_id
      LEFT JOIN season ON season.competition_id= competition.id
      LEFT JOIN round ON round.season_id= season.id
      LEFT JOIN match ON match.round_id= round.id
      WHERE match.datetime = " . $args["date"] . ""