【问题标题】:Thread C++ member function template variadic template线程 C++ 成员函数模板 可变参数模板
【发布时间】:2016-04-24 15:59:52
【问题描述】:

我尝试使用线程调用对象的成员函数。

如果函数没有可变参数模板(Args ... args),没问题,它可以工作:

考虑两个类:

基因引擎

template <class T>
class GeneticEngine
{
    template <typename ... Args>
    T* run_while(bool (*f)(const T&),const int size_enf,Args& ... args)
    {
         std::thread(&GeneticThread<T>::func,islands[0],f,size_enf);
         /* Some code */
         return /* ... */
    }
    private:
        GeneticThread<T>** islands;


}

基因线程

template <class T>
class GeneticThread
{
    void func(bool (*f)(const T&),const int size_enf)
    {
        /* Some code */
    };
}

有了这个就OK了。


现在,我将可变参数模板添加到相同的函数中:

基因引擎

template <class T>
class GeneticEngine
{
    template <typename ... Args>
    T* run_while(bool (*f)(const T&,Args& ...),const int size_enf,Args& ... args)
    {
       std::thread(&GeneticThread<T>::func,islands[0],f,size_enf,args ...);
       /* Other code ... */
    }
    private:
        GeneticThread<T>** islands;
}

基因线程

template <class T>
class GeneticThread
{
    template <typename ... Args>
    void func(bool (*f)(const T&,Args& ...), const int size_enf, Args& ... args)
    {
       /* Code ... */
    };
 }

使用此代码,GCC 无法编译:(对于此错误消息感到抱歉)

g++ main.cpp GeneticEngine.hpp GeneticThread.hpp Individu.hpp GeneticThread.o -g -std=c++0x    -o main.exe
In file included from main.cpp:2:0:
GeneticEngine.hpp: In instantiation of ‘T* GeneticEngine<T>::run_while(bool (*)(const T&, Args& ...), int, Args& ...) [with Args = {}; T = Individu]’:
main.cpp:24:78:   required from here
GeneticEngine.hpp:20:13: erreur: no matching function for call to ‘std::thread::thread(<unresolved overloaded function type>, GeneticThread<Individu>*&, bool (*&)(const Individu&), const int&)’
GeneticEngine.hpp:20:13: note: candidates are:
In file included from GeneticThread.hpp:14:0,
             from GeneticEngine.hpp:4,
             from main.cpp:2:
/usr/include/c++/4.7/thread:131:7: note: template<class _Callable, class ... _Args> std::thread::thread(_Callable&&, _Args&& ...)
/usr/include/c++/4.7/thread:131:7: note:   template argument deduction/substitution failed:
In file included from main.cpp:2:0:
GeneticEngine.hpp:20:13: note:   couldn't deduce template parameter ‘_Callable’
In file included from GeneticThread.hpp:14:0,
             from GeneticEngine.hpp:4,
             from main.cpp:2:
/usr/include/c++/4.7/thread:126:5: note: std::thread::thread(std::thread&&)
/usr/include/c++/4.7/thread:126:5: note:   candidate expects 1 argument, 4 provided
/usr/include/c++/4.7/thread:122:5: note: std::thread::thread()
/usr/include/c++/4.7/thread:122:5: note:   candidate expects 0 arguments, 4 provided

我真的不明白为什么这种差异会导致这个错误。而且我无法修复它。


在main.cpp中都是这样的:

/* Individu is another class */

int pop_size = 1000;
int pop_child = pop_size*0.75;

GeneticEngine<Individu> engine(/*args to constructor*/);

bool (*stop)(const Individu&) = [](const Individu& best){
    return false;
};
Individu* best = engine.run_while(stop,pop_child);

我使用:«gcc 版本 4.7.2 (Ubuntu/Linaro 4.7.2-2ubuntu1) »


我试过了:

std::thread(&GeneticThread<T>::func<Args...>, islands[0], f, size_enf, args ...);

现在我有另一个错误:

GeneticEngine.hpp: In member function ‘T* GeneticEngine<T>::run_while(bool (*)(const T&, Args& ...), int, Args& ...)’:
GeneticEngine.hpp:20:53: erreur: expansion pattern ‘((& GeneticThread<T>::func) < <expression error>)’ contains no argument packs
GeneticEngine.hpp:20:24: erreur: expected primary-expression before ‘(’ token
GeneticEngine.hpp:20:53: erreur: expected primary-expression before ‘...’ token



template <typename ... Args>
T* run_while(bool (*f)(const T&,Args& ...), const int size_enf, Args& ... args)
{

   void (GeneticThread<T>::*ptm)(bool (*)(T const&, Args&...), int, Args&...) = &GeneticThread<T>::func;
   std::thread(ptm, islands[0], f, size_enf, args ...);
}

【问题讨论】:

  • 试试&amp;GenericThread&lt;T&gt;::func&lt;Args...&gt;
  • 看起来 GCC 在模式扩展方面遇到了问题。您可以分别尝试auto ptm = &amp;GenericThread&lt;T&gt;::func&lt;Args...&gt;;void (GenericThread&lt;T&gt;::*ptm)(bool (*)(T const&amp;, Args&amp;...), int, Args&amp;...) = &amp;GenericThread&lt;T&gt;::func;,然后将ptm 传递给std::thread 构造函数吗?
  • 非常感谢@Luc Danton。
  • 尽可能简洁,函数模板不是函数,也不存在获取函数模板地址的事情。相反,在这种情况下,函数模板的名称表现得好像它是函数重载集的名称。在获取重载函数的地址时,请参阅this。 (但是 GCC 不能获取函数模板特化的地址应该是一个 bug。)
  • 谢谢,我现在明白了。

标签: c++ multithreading templates c++11


【解决方案1】:

试试:

std::thread(&GeneticThread<T>::func<Args...>, islands...

func 现在是一个模板函数。您必须指定其模板参数才能获取其地址。

【讨论】:

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