【发布时间】:2013-10-11 02:56:18
【问题描述】:
当我在下面的代码中运行时,我的预期输出是播放器应该连续动画,并且当用户点击屏幕时播放器应该跳跃。我的播放器的帧不同,跳帧也不同。我在鼠标左键单击时调用帧。所有帧都已处理,但速度太快,因此动画不可见。
private void OnUpdate(object sender, GameTimerEventArgs e)
{
float elapsed = (float)e.ElapsedTime.TotalSeconds;
timer5 -= elapsed;
TouchPanel.EnabledGestures = GestureType.Tap;
TouchCollection touches = TouchPanel.GetState();
MouseState mousestate = Mouse.GetState();
//Texture.position += velocity;
//if (rect.Contains(new Microsoft.Xna.Framework.Point(mousestate.X, mousestate.Y)) && mousestate.LeftButton == ButtonState.Pressed)
if (mousestate.LeftButton==ButtonState.Pressed)
{
for (int i = 0; i < 32; i++)
{
jump();
jumpframe++;
if (jumpframe > 24)
{
jumpframe = 0;
}
System.Diagnostics.Debug.WriteLine("currentframe:"+ jumpframe);
}
}
if (timer5 <= 0)
{
playerr();
currentframe++;
if (currentframe > 24)
{
currentframe = 0;
}
timer5 = TIME_BET_FRAME;
}
}
private void OnDraw(object sender, GameTimerEventArgs e)
{
SharedGraphicsDeviceManager.Current.GraphicsDevice.Clear(Color.CornflowerBlue);
spriteBatch.Begin();
//level.Draw(spriteBatch);
rect2 = new Rectangle(0, 0, 960, 620);
rect = new Rectangle(0, 0, 420, 300);
spriteBatch.Draw(Texture.player[currentframe], Texture.position, Color.White);
spriteBatch.Draw(Texture.jumpplayer[jumpframe], Texture.jumpposition, Color.White);
spriteBatch.Draw(Texture.jumpbtn, Texture.rect, Color.White);
spriteBatch.DrawString(font, "Score", new Vector2(10, 0), Color.Gold);
spriteBatch.End();
}
public void jump()
{
Texture.jumpposition.X = 10;
Texture.jumpposition.Y = 243;
Texture.position.X = -400;
Texture.position.Y = 243;
}
public void playerr()
{
Texture.position.X = 10;
Texture.position.Y = 243;
Texture.jumpposition.X = -400;
Texture.jumpposition.Y = 243;
}
【问题讨论】:
-
您已经说明了问题 - “太快了”。通过创建计时器分割作业来减慢速度。
-
@Sinatr 我已经将 timer5 用于播放器.......所以现在我可以将它用于 jumpplayer 吗???...thnx 用于响应
-
也可以使用一些比较容易理解的变量名(而不是timer5、rect2、something2000),等项目长大一个月后就会迷路。
标签: c# windows-phone-7 xna