如何通过比较 JavaScript 中今天的格式化日期来检查未来日期？答案

【问题标题】：How to check future date by comparing today's formatted date in javaScript?如何通过比较 JavaScript 中今天的格式化日期来检查未来日期？
【发布时间】：2018-10-18 22:09:33
【问题描述】：

如何通过比较javascript中今天的格式化日期来检查未来的日期？所需的变量在下面的代码中注释。

var formattedDate = new Date();
var d = formattedDate.getDate();
var m =  formattedDate.getMonth();
m += 1;
var tomorrowDay = d + 1;
var y = formattedDate.getFullYear();
var todayDate = y + "-" + m + "-" + d;
var tomorrowDate = y + "-" + m + "-" + tomorrowDay;
var futureDate = ??? //Logic Needed

if (this.data) {
var Items = this.data.itemCollectionData;

for (var i = 0; i < dealItems.length; i++) {

if (Items[i].showDate == todayDate) {
Items[i].isToday = true;
} else if (Items[i].showDate == tomorrowDate) {
Items[i].isTomorrow = true;
} else if (Items[i].showDate == futureDate) {
Items[i].isFutureDate = true;
}
}
}

futureDate 可能是后天的任何一天，也可能是明年或下个月。明天的逻辑也需要更正，因为它在本月的最后一天不起作用。 Items[i].showDate 总是以这种格式 yyyy-mm-dd 的字符串形式出现。

【问题讨论】：

什么是futureDate？后天？下周的某个时间？下个月？明年？此外，您的“明天”逻辑存在问题：例如，如果日期是 2018 年 10 月 31 日，您最终会得到 2018-10-32，这是无效的。你应该看看Moment。
Compare two dates with JavaScript的可能重复
futureDate 可能是后天的任何一天，可能是明年或下个月。关于明天的逻辑很好！也需要一个正确的逻辑。 Items[i].showDate 总是以这种格式 yyyy-mm-dd 的字符串形式出现。
注意拼写 JavaScript。 javascriptisnotjava.io

标签： javascript

【解决方案1】：

改编自这个答案：Adding hours to Javascript Date object?

理论是通过将所需的毫秒数添加到当前日期，并根据结果创建一个新日期 - 应考虑月份/闰年的天数

var numberOfDaysInFuture = 10;


var formattedDate = new Date();
var d = formattedDate.getDate();
var m = formattedDate.getMonth();
m += 1;
var y = formattedDate.getFullYear();
var todayDate = y + "-" + m + "-" + d;

// tomorrows +1 fix
var tomorrowDateObject = addDaysToDate(formattedDate, 1);
var tomorrowDate = tomorrowDateObject.getFullYear() + "-" + (tomorrowDateObject.getMonth() + 1) + "-" + tomorrowDateObject.getDate();

// create future date
var futureDateObject = addDaysToDate(formattedDate, numberOfDaysInFuture);
var futureDate = futureDateObject.getFullYear() + "-" + (futureDateObject.getMonth() + 1) + "-" + futureDateObject.getDate();

if (this.data) {
  var Items = this.data.itemCollectionData;

  for (var i = 0; i < dealItems.length; i++) {

    if (Items[i].showDate == todayDate) {
      Items[i].isToday = true;
    } else if (Items[i].showDate == tomorrowDate) {
      Items[i].isTomorrow = true;
    } else if (Items[i].showDate == futureDate) {
      Items[i].isFutureDate = true;
    }
  }
}

console.log("TODAY : " + todayDate)
console.log("TOMORROW : " + tomorrowDate)
console.log("FUTURE : " + futureDate);

// https://stackoverflow.com/questions/1050720/adding-hours-to-javascript-date-object
function addDaysToDate(date, days) {
  // would be easy enough to change to years, days.. whatever you need
  return new Date(date.getTime() + (days * 24 * 60 * 60 * 1000));
}

【讨论】：

【解决方案2】：

var numberOfDaysInFuture = 10;


var formattedDate = new Date();
var d = formattedDate.getDate();
var m = formattedDate.getMonth();
m += 1;
var y = formattedDate.getFullYear();
var todayDate = y + "-" + m + "-" + d;

// tomorrows +1 fix
var tomorrowDateObject = addDaysToDate(formattedDate, 1);
var tomorrowDate = tomorrowDateObject.getFullYear() + "-" + (tomorrowDateObject.getMonth() + 1) + "-" + tomorrowDateObject.getDate();

// create future date
var futureDateObject = addDaysToDate(formattedDate, numberOfDaysInFuture);
var futureDate = futureDateObject.getFullYear() + "-" + (futureDateObject.getMonth() + 1) + "-" + futureDateObject.getDate();

if (this.data) {
  var Items = this.data.itemCollectionData;

  for (var i = 0; i < dealItems.length; i++) {

    if (Items[i].showDate == todayDate) {
      Items[i].isToday = true;
    } else if (Items[i].showDate == tomorrowDate) {
      Items[i].isTomorrow = true;
    } else if (Items[i].showDate == futureDate) {
      Items[i].isFutureDate = true;
    }
  }
}

console.log("TODAY : " + todayDate)
console.log("TOMORROW : " + tomorrowDate)
console.log("FUTURE : " + futureDate);

// https://stackoverflow.com/questions/1050720/adding-hours-to-javascript-date-object
function addDaysToDate(date, days) {
  // would be easy enough to change to years, days.. whatever you need
  return new Date(date.getTime() + (days * 24 * 60 * 60 * 1000));
}

【讨论】：