拆分文件夹中的文本文件

Question

我一直在尝试制作一个 shell 脚本，它会在整个文件夹中一个接一个地拆分文本文件，并将每个拆分的块存放到另一个指定的文件夹中。

这是我目前所拥有的，我知道它可能很笨重（以前从未尝试过编写 .sh）：

#!/bin/bash
#File Split Automation

echo "Usage: split [Folder w/ Input] [Folder For Outputs] [Options] [PREFIX]
  Options: -b [sizeMB]: Split by size
  -l [No. of Lines]: Split by Lines
  If No Output Folder is Defined Default is Set To: /Desktop/splitter-parts
  If No Options Are Selected Default is Size=100MB"

inputdirc=$1
outputdirc=$2
spltion=$3
meastick=$4
prefixture=$5

if [ -d $1 ]
then
    echo "You Picked The Folder $1 To Split Files From"
    ls $1
else
    exit
fi

if [ -d $2 ]
then
    echo "Please Confirm Folder Path For Output $outputdirc"
else
    cd /root/Desktop/
    mkdir -p splitter-parts
fi



read -t 10 -p "Press Enter Or Wait 5 Sec. To Continue"


cd $2

for swordfile in $( ls $1); 
do
command -p split $3 $4 -a 3 -d $swordfile $5

done

你发现有什么问题吗？因为我没有得到我想要的输出，尽管当我在拆分命令字符串中有一个文件和一个文件夹时它运行良好。

编辑::::

对不起，我很抱歉。只是有点超前了。

这是我运行它时看到的：

root@kali:~/Desktop/Wordlists# ./splitter.sh '/root/Desktop/Wordlists'               '   /root/Desktop/Untitled Folder' s 100MB
Usage: split [Folder w/ Input] [Folder For Outputs] [Options] [PREFIX]
Options: -b [sizeMB]: Split by size
-l [No. of Lines]: Split by Lines
If No Output Folder is Defined Default is Set To: /Desktop/splitter-parts
If No Options Are Selected Default is Size=100MB
You Picked The Folder /root/Desktop/Wordlists To Split Files From
10dig10milup2.txt                     mixed.txt
10dig10miluplow2.txt                      movie-characters.txt
10dig10miluplow3.txt                      name1s.txt
((------------------CUT------------)
lower.lst                         xae2.txt
lower.txt                         xaf2.txt
mangled.lst                       xag2.txt
mangled.txt                       xah6.txt
misc-dictionary.txt
./splitter.sh: line 24: [: /root/Desktop/Untitled: binary operator expected
Press Enter Or Wait 5 Sec. To Continue
./splitter.sh: line 37: cd: /root/Desktop/Untitled: No such file or directory
split: extra operand `10dig10milup2.txt'
Try `split --help' for more information.
split: extra operand `10dig10miluplow2.txt'
Try `split --help' for more information.
split: extra operand `10dig10miluplow3.txt'
Try `split --help' for more information.
split: extra operand `10dig10miluplow4.txt'
Try `split --help' for more information.
...................MORE OF THE SAME.......

就我应该看到的而言，我还没有走那么远，显然我错过了一些步骤。

Answer 1

快速重写并附上一些注释：

#!/bin/bash
#File Split Automation

usage="Usage: split [Options] [Folder w/ Input] [Folder For Outputs] [PREFIX]
  Options: -b [sizeMB]: Split by size
  -l [No. of Lines]: Split by Lines
  If No Output Folder is Defined Default is Set To: /Desktop/splitter-parts
  If No Options Are Selected Default is Size=100MB"

split_opt="-b 100MB"
while getopts hb:l: opt; do
    case $opt in
        h) echo "$usage"; exit ;;
        b) split_opt="-b $OPTARG" ;;
        l) split_opt="-l $OPTARG" ;;
    esac
done
shift $((OPTIND - 1))

if [[ $# -eq 0 ]]; then
    echo "$usage"
    exit 1
fi

inputdirc=$1
if [[ -d $inputdirc ]]; then
    ls $1
else
    echo "no such directory: $inputdirc" >&2
    exit 1
fi

if [[ -n $2 ]]; then
    outputdirc=$2
else
    outputdirc=/root/Desktop/splitter-parts
fi

prefixture=$3

mkdir -p "$outputdirc"
cd "$outputdirc"

for swordfile in "$inputdirc"/*; do
    command -p split $split_opt -a 3 -d "$swordfile" $prefixture 
done

注意事项：

• 您通常希望引用所有您的变量。这是您的错误的原因，因为名称中有一个带有空格和方括号的文件。
• 我没有在 split 命令中引用一对，因为我特别希望 shell 对值执行 word splitting
• 既然选项是可选的，请使用getopts 收集它们。
• 您将位置参数存储在变量中，但您继续使用位置参数。任选其一。