此命令创建一个包含 0 和 1 的表。
table(do.call(rbind, lapply(c("M1", "M2", "M3", "M4"), function(x)
data.frame(ind = x, var = get(x)))))
var
ind Variable_1 Variable_2 Variable_3 Variable_4 Variable_5
M1 1 1 1 0 0
M2 0 1 0 1 1
M3 0 0 1 0 0
M4 1 1 1 1 1
如果你真的想拥有xs,你可以使用:
tab <- table(do.call(rbind, lapply(c("M1", "M2", "M3", "M4"), function(x)
data.frame(ind = x, var = get(x)))))
replace(replace(tab, as.logical(tab), "x"), !tab, "")
var
ind Variable_1 Variable_2 Variable_3 Variable_4 Variable_5
M1 x x x
M2 x x x
M3 x
M4 x x x x x
根据您的评论。如何摆脱var和ind以及如何使用列表:
LL <- list(M1, M2, M3, M4)
tab <- table(do.call(rbind, lapply(seq_along(LL), function(x)
data.frame(ind = x, var = LL[[x]]))))
dimnames(tab) <- unname(dimnames(tab))
replace(replace(tab, as.logical(tab), "x"), !tab, "")
Variable_1 Variable_2 Variable_3 Variable_4 Variable_5
1 x x x
2 x x x
3 x
4 x x x x x