Socket.io，从客户端获得两个响应然后运行代码？

Question

我想让答案验证仅在从客户端收到两个唯一响应后才触发。

var nrecieved = 0;
var responses = {}; // Socket id to response

function finish(){
   // Loop through users in game and send them their responses
   for(var id in responses){
        if(responses.hasOwnProperty(id)){
             // Send the response
             io.to(id).emit('updatePlayer', responses[id]);
        }
   }
}

socket.on('playerCorrect', function (data) {
    nrecieved++;
    responses[socket.id] = data;
    answerValidation(nrecieved);
});    

socket.on('playerWrong', function (data) {
    nrecieved++;
    responses[socket.id] = data;
    answerValidation(nrecieved);
}); 

console.log(nrecieved);
function answerValidation(value) {
    nrecieved = value + value;
    console.log(value);
    if(nrecieved == 2){
        finish();
        dataRequest();
    } 
}

问题是我不能真正使用 nrecieved++；在那些套接字事件中，否则它不会正确计数。如果玩游戏的客户必须选择他们的答案并且会触发套接字事件然后 ++，有没有办法触发计数器？

Answer 1

var nPlayers = 2; // Total number of players to process at a time
var responses = {}; // Socket id to response

var finish = function(){
   // Loop through users in game and send them their responses
   for(var id in responses){
        if(responses.hasOwnProperty(id)){
             // Send the response
             io.to(id).emit('updatePlayer', responses[id]);
        }
   }
}

var answerValidation = function() {
    // number of players reached
    if(Object.keys(responses).length === nPlayers){
        finish();
        dataRequest();
    } 
    // reset responses
    responses = {};
}

var registerAnswer = function(id, data) {
    // check for existing response from this player
    // disallows overwriting answers until processed
    if(!responses.hasOwnProperty(id) {
        responses[id] = data;
        answerValidation();
    }
};

socket.on('playerCorrect', function (data) {
    registerAnswer(socket.id, data);
});    

socket.on('playerWrong', function (data) {
    registerAnswer(socket.id, data);
});