【发布时间】:2014-05-09 08:13:15
【问题描述】:
更新 谢谢您解决了问题,但现在我收到此错误“连接尝试失败,因为连接方在一段时间后没有正确响应或建立连接失败,因为连接的主机没有响应。”我关闭了防火墙并我没有任何杀毒软件
我正在按照本教程将 android 应用程序连接到数据库 http://www.androidhive.info/2012/05/how-to-connect-android-with-php-mysql/
我在 WAMPSERVER PHP 版本 5.4.3 中托管我的 php 文件我收到这两个错误 我已经尝试修复这个错误好几个小时了,但没有运气,请你帮我修复它
" 警告:require_once(C:\wamp\wwwC:\wamp\www\db_connect.php):无法打开流:C:\wamp\www\get_property_details.php 第 12 行中的参数无效"
还有这个错误
“致命错误:require_once(): 无法在 C 中打开所需的 'C:\wamp\wwwC:\wamp\www\db_connect.php' (include_path='.;C:\php\pear') :\wamp\www\get_property_details.php 第 12 行"
这些是我的文件 db_config.php
define('DB_USER', "student");
define('DB_PASSWORD', "student2");
define('DB_DATABASE', "test");
define('DB_SERVER', "student.database.university.ac.uk");
?>
db_connect.php
<?php
class DB_CONNECT {
function __construct() {
$this->connect();
}
function __destruct() {
$this->close();
}
function connect() {
require_once __DIR__ . "C:\\wamp\\www\\db_config.php";
$con = mysql_connect(DB_SERVER, DB_USER, DB_PASSWORD) or die(mysql_error());
$db = mysql_select_db(DB_DATABASE) or die(mysql_error()) or die(mysql_error());
return $con;
}
function close() {
mysql_close();
}
}
?>
get_student_details.php
<?php
/*
* Following code will get single student details
* A student is identified by student id (student_id)
*/
// array for JSON response
$response = array();
// include db connect class
require_once __DIR__ . "C:\\wamp\\www\\db_connect.php";
// connecting to db
$db = new DB_CONNECT();
// check for post data
if (isset($_GET["student_id"])) {
$student_id = $_GET['student_id'];
// get a student from students table
$result = mysql_query("SELECT * FROM TABLE_STUDENT WHERE student_id = $student_id");
if (!empty($result)) {
// check for empty result
if (mysql_num_rows($result) > 0) {
$result = mysql_fetch_array($result);
$student = array();
$student["student_id"] = $result["student_id"];
$student["student_fname"] = $result["student_fname"];
$student["student_lastName"] = $result["student_lastName"];
$student["address"] = $result["address"];
$student["postcode"] = $result["postcode"];
$student["grade"] = $result["grade"];
// success
$response["success"] = 1;
// user node
$response["student"] = array();
array_push($response["student"], $student);
// echoing JSON response
echo json_encode($response);
} else {
// no student found
$response["success"] = 0;
$response["message"] = "No student found";
// echo no users JSON
echo json_encode($response);
}
} else {
// no student found
$response["success"] = 0;
$response["message"] = "No student found";
// echo no users JSON
echo json_encode($response);
}
} else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";
// echoing JSON response
echo json_encode($response);
}
?>
【问题讨论】:
-
快速注意,您应该远离 mysql 并使用 mysqli,因为 mysql 已被弃用并将被删除