如何创建 Sql Server 2008 跨表动态查询？答案

【问题标题】：How to create Sql Server 2008 Cross Tab Dynamic Query?如何创建 Sql Server 2008 跨表动态查询？
【发布时间】：2012-11-14 23:39:52
【问题描述】：

我有 3 张桌子：

地点：LocationID, LocationName
缺陷：DefectID, DefectType
反馈：feedbackID, DefectID, LocationID

我需要以下格式的交叉表报告：位置列下方的数字是该位置的缺陷总数。位置可以是任意数字。它应该是动态的..

DefectID  DefectType  NewYork  NewJersey  Texas  Houston
1         Defect1       0         10        3       6
2         Defect2       0          0        9      10
3         Defect3       8          8        4       6

我有一个硬编码的 SQL 查询。此外，它没有显示DefectID..

select 
   DefectType, 
   [1] as NewYork, 
   [4] as NewJersy,  
   [5] as Texas, 
   [6] as Houston
from (select 
             Defect.DefectID, 
             Defect.DefectType, 
             Location.LocationID  
      from Feedback
      inner join Locations on (Feedback.LocationID= Location.LocationID)             
      inner join DefectType on (Feedback.DefectID= Defect.DefectID)         
     ) p
    pivot   
     ( count (DefectID) for LocationID in ( [1], [4], [5],[6] )   ) as pvt
 order by pvt.DefectType;

【问题讨论】：

标签： sql sql-server-2008

【解决方案1】：

您不能使用 SQL Server PIVOT 和纯静态 SQL 动态构建交叉表值。您必须动态构建 SQL，或者使用一些外部脚本语言构建查询，或者使用 T-SQL 使用 execute

DECLARE @locationID int, @LocationName nvarchar(50), 
  @columnList nvarchar(max), @idList nvarchar(max), @sql nvarchar(max) ;
DECLARE location_cursor CURSOR
    FOR SELECT locationID, LocationName FROM Locations

SET @columnList = '';
SET @idList = '';


OPEN location_cursor
FETCH NEXT FROM vendor_cursor 
INTO @locationID, @LocationName;
WHILE @@FETCH_STATUS = 0
BEGIN
  SET @columnList = @columnList + ', [' + @locationID + '] as [' + @locationName + ']'
  SET @idList = @idList + '[' + @locationID + '],'
END
CLOSE location_cursor

SET @sql = 'select DefectType' + @columnList + ' from (select Defect.DefectID, Defect.DefectType, Location.LocationID from Feedback inner join Locations on (Feedback.LocationID= Location.LocationID)
inner join DefectType on (Feedback.DefectID= Defect.DefectID)
) p pivot
( count (DefectID) for LocationID in (' + left(@idList,len(@idList)-1) + ') ) as pvt order by pvt.DefectType'

EXECUTE (@sql)

显然，我还没有对此进行测试，但它应该可以工作（可能需要稍作调整）。

【讨论】：